Return random `list` item by its `weight`

http://programmers.stackexchange.com/questions/150616/return-random-list-item-by-its-weight

public int chooseWithChance(params int[] args)

{
    /*
     * This method takes number of chances and randomly chooses
     * one of them considering their chance to be choosen.    
     * e.g. 
     *   chooseWithChance(1,99) will most probably (%99) return 1 since 99 is the second parameter.
     *   chooseWithChance(99,1) will most probably (%99) return 0 since 99 is the first parameter.     
     */
    int argCount = args.Length;
    int sumOfChances = 0;

    for (int i = 0; i < argCount; i++) {
        sumOfChances += args[i];
    }

    int random = new Random(DateTime.Now.Millisecond).Next(sumOfChances);

    while ((random -=args[argCount-1])> 0)
    {
        argCount--;
        sumOfChances -= args[argCount -1];
    }

    return argCount-1;
}

string[] fruits = new string[] { "apple", "orange", "lemon" };
int choosenOne = chooseWithChance(4,2,1);
Console.WriteLine(fruits[choosenOne]);